Solve for x
x=-\frac{y}{4}+\frac{65}{6}
Solve for y
y=\frac{130}{3}-4x
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12x-128=2-3y
Subtract 3y from both sides.
12x=2-3y+128
Add 128 to both sides.
12x=130-3y
Add 2 and 128 to get 130.
\frac{12x}{12}=\frac{130-3y}{12}
Divide both sides by 12.
x=\frac{130-3y}{12}
Dividing by 12 undoes the multiplication by 12.
x=-\frac{y}{4}+\frac{65}{6}
Divide 130-3y by 12.
3y-128=2-12x
Subtract 12x from both sides.
3y=2-12x+128
Add 128 to both sides.
3y=130-12x
Add 2 and 128 to get 130.
\frac{3y}{3}=\frac{130-12x}{3}
Divide both sides by 3.
y=\frac{130-12x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{130}{3}-4x
Divide 130-12x by 3.
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