Solve 125-(x-y)*5-(x-0.2z)*7.5=0

$$125-(x-y) \times 5-(x-0.2z) \times 7.5=0$$

Solve for x

$$x=\frac{2y}{5}+\frac{3z}{25}+10$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-y by 5.

$$125-\left(5x-5y\right)-\left(x-0.2z\right)\times 7.5=0$$

To find the opposite of 5x-5y, find the opposite of each term.

$$125-5x+5y-\left(x-0.2z\right)\times 7.5=0$$

Use the distributive property to multiply x-0.2z by 7.5.

$$125-5x+5y-\left(7.5x-1.5z\right)=0$$

To find the opposite of 7.5x-1.5z, find the opposite of each term.

$$125-5x+5y-7.5x+1.5z=0$$

Combine -5x and -7.5x to get -12.5x.

$$125-12.5x+5y+1.5z=0$$

Subtract 125 from both sides. Anything subtracted from zero gives its negation.

$$-12.5x+5y+1.5z=-125$$

Subtract 5y from both sides.

$$-12.5x+1.5z=-125-5y$$

Subtract 1.5z from both sides.

$$-12.5x=-125-5y-1.5z$$

The equation is in standard form.

$$-12.5x=-\frac{3z}{2}-5y-125$$

Divide both sides of the equation by -12.5, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-12.5x}{-12.5}=\frac{-\frac{3z}{2}-5y-125}{-12.5}$$

Dividing by -12.5 undoes the multiplication by -12.5.

$$x=\frac{-\frac{3z}{2}-5y-125}{-12.5}$$

Divide -125-5y-\frac{3z}{2} by -12.5 by multiplying -125-5y-\frac{3z}{2} by the reciprocal of -12.5.

$$x=\frac{2y}{5}+\frac{3z}{25}+10$$

Solve for y

$$y=\frac{5x}{2}-\frac{3z}{10}-25$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-y by 5.

$$125-\left(5x-5y\right)-\left(x-0.2z\right)\times 7.5=0$$

To find the opposite of 5x-5y, find the opposite of each term.

$$125-5x+5y-\left(x-0.2z\right)\times 7.5=0$$

Use the distributive property to multiply x-0.2z by 7.5.

$$125-5x+5y-\left(7.5x-1.5z\right)=0$$

To find the opposite of 7.5x-1.5z, find the opposite of each term.

$$125-5x+5y-7.5x+1.5z=0$$

Combine -5x and -7.5x to get -12.5x.

$$125-12.5x+5y+1.5z=0$$

Subtract 125 from both sides. Anything subtracted from zero gives its negation.

$$-12.5x+5y+1.5z=-125$$

Add 12.5x to both sides.

$$5y+1.5z=-125+12.5x$$

Subtract 1.5z from both sides.

$$5y=-125+12.5x-1.5z$$

The equation is in standard form.

$$5y=\frac{25x}{2}-\frac{3z}{2}-125$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{\frac{25x}{2}-\frac{3z}{2}-125}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{\frac{25x}{2}-\frac{3z}{2}-125}{5}$$

Divide -125+\frac{25x}{2}-\frac{3z}{2} by 5.

$$y=\frac{5x}{2}-\frac{3z}{10}-25$$