Factor
\left(5z-7\right)\left(25z^{2}+35z+49\right)
Evaluate
125z^{3}-343
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\left(5z-7\right)\left(25z^{2}+35z+49\right)
Rewrite 125z^{3}-343 as \left(5z\right)^{3}-7^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 25z^{2}+35z+49 is not factored since it does not have any rational roots.
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