Factor
\left(5y+2\right)\left(25y^{2}-10y+4\right)
Evaluate
125y^{3}+8
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\left(5y+2\right)\left(25y^{2}-10y+4\right)
Rewrite 125y^{3}+8 as \left(5y\right)^{3}+2^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial 25y^{2}-10y+4 is not factored since it does not have any rational roots.
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