Factor
\left(5x-2\right)\left(25x^{2}+10x+4\right)
Evaluate
125x^{3}-8
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\left(5x-2\right)\left(25x^{2}+10x+4\right)
Rewrite 125x^{3}-8 as \left(5x\right)^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 25x^{2}+10x+4 is not factored since it does not have any rational roots.
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