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\left(5x-6b\right)\left(25x^{2}+30bx+36b^{2}\right)
Rewrite 125x^{3}-216b^{3} as \left(5x\right)^{3}-\left(6b\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).