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125^{2v}=25
Use the rules of exponents and logarithms to solve the equation.
\log(125^{2v})=\log(25)
Take the logarithm of both sides of the equation.
2v\log(125)=\log(25)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2v=\frac{\log(25)}{\log(125)}
Divide both sides by \log(125).
2v=\log_{125}\left(25\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
v=\frac{\frac{2}{3}}{2}
Divide both sides by 2.