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125+2\times 3\sqrt{5}-3
Factor 45=3^{2}\times 5. Rewrite the square root of the product \sqrt{3^{2}\times 5} as the product of square roots \sqrt{3^{2}}\sqrt{5}. Take the square root of 3^{2}.
125+6\sqrt{5}-3
Multiply 2 and 3 to get 6.
122+6\sqrt{5}
Subtract 3 from 125 to get 122.