Solve for x
x=-\frac{3y}{4}+10
Solve for y
y=\frac{40-4x}{3}
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120x=1200-90y
Subtract 90y from both sides.
\frac{120x}{120}=\frac{1200-90y}{120}
Divide both sides by 120.
x=\frac{1200-90y}{120}
Dividing by 120 undoes the multiplication by 120.
x=-\frac{3y}{4}+10
Divide 1200-90y by 120.
90y=1200-120x
Subtract 120x from both sides.
\frac{90y}{90}=\frac{1200-120x}{90}
Divide both sides by 90.
y=\frac{1200-120x}{90}
Dividing by 90 undoes the multiplication by 90.
y=\frac{40-4x}{3}
Divide 1200-120x by 90.
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