Solve 12000(1-0.01x)^2=9720

$$12000 ( 1 - 0.01 x ) ^ { 2 } = 9720$$

Solve for x

$$x=10$$

$$x=190$$

Steps by Finding Square Root

Divide both sides by 12000.

$$\frac{12000\left(-0.01x+1\right)^{2}}{12000}=\frac{9720}{12000}$$

Dividing by 12000 undoes the multiplication by 12000.

$$\left(-0.01x+1\right)^{2}=\frac{9720}{12000}$$

Reduce the fraction \frac{9720}{12000} to lowest terms by extracting and canceling out 120.

$$\left(-0.01x+1\right)^{2}=\frac{81}{100}$$

Take the square root of both sides of the equation.

$$-0.01x+1=\frac{9}{10} -0.01x+1=-\frac{9}{10}$$

Subtract 1 from both sides of the equation.

$$-0.01x+1-1=\frac{9}{10}-1 -0.01x+1-1=-\frac{9}{10}-1$$

Subtracting 1 from itself leaves 0.

$$-0.01x=\frac{9}{10}-1 -0.01x=-\frac{9}{10}-1$$

Subtract 1 from \frac{9}{10}.

$$-0.01x=-\frac{1}{10}$$

Subtract 1 from -\frac{9}{10}.

$$-0.01x=-\frac{19}{10}$$

Multiply both sides by -100.

$$\frac{-0.01x}{-0.01}=-\frac{\frac{1}{10}}{-0.01} \frac{-0.01x}{-0.01}=-\frac{\frac{19}{10}}{-0.01}$$

Dividing by -0.01 undoes the multiplication by -0.01.

$$x=-\frac{\frac{1}{10}}{-0.01} x=-\frac{\frac{19}{10}}{-0.01}$$

Divide -\frac{1}{10} by -0.01 by multiplying -\frac{1}{10} by the reciprocal of -0.01.

$$x=10$$

Divide -\frac{19}{10} by -0.01 by multiplying -\frac{19}{10} by the reciprocal of -0.01.

$$x=190$$

The equation is now solved.

$$x=10 x=190$$