Solve 12.5y+3x=13x-30

$$12.5y+3x=13x-30$$

Solve for x

$$x=\frac{5y}{4}+3$$

Steps for Solving Linear Equation

Subtract 13x from both sides.

$$12.5y+3x-13x=-30$$

Combine 3x and -13x to get -10x.

$$12.5y-10x=-30$$

Subtract 12.5y from both sides.

$$-10x=-30-12.5y$$

The equation is in standard form.

$$-10x=-\frac{25y}{2}-30$$

Divide both sides by -10.

$$\frac{-10x}{-10}=\frac{-\frac{25y}{2}-30}{-10}$$

Dividing by -10 undoes the multiplication by -10.

$$x=\frac{-\frac{25y}{2}-30}{-10}$$

Divide -30-\frac{25y}{2} by -10.

$$x=\frac{5y}{4}+3$$

Solve for y

$$y=\frac{4\left(x-3\right)}{5}$$

Steps for Solving Linear Equation

Subtract 3x from both sides.

$$12.5y=13x-30-3x$$

Combine 13x and -3x to get 10x.

$$12.5y=10x-30$$

Divide both sides of the equation by 12.5, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{12.5y}{12.5}=\frac{10x-30}{12.5}$$

Dividing by 12.5 undoes the multiplication by 12.5.

$$y=\frac{10x-30}{12.5}$$

Divide -30+10x by 12.5 by multiplying -30+10x by the reciprocal of 12.5.

$$y=\frac{4x-12}{5}$$