Solve for x
x\geq \frac{2}{3}
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12x\geq -1+9
Add 9 to both sides.
12x\geq 8
Add -1 and 9 to get 8.
x\geq \frac{8}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\geq \frac{2}{3}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
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Matrix
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Limits
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