Solve for x
x\leq \frac{2}{3}
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12x-8\leq 0
Subtract 1 from -7 to get -8.
12x\leq 8
Add 8 to both sides. Anything plus zero gives itself.
x\leq \frac{8}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\leq \frac{2}{3}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
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