Solve 12x-33y-2=01

$$12 x - 33 y - 2 = 01$$

Solve for x

$$x=\frac{11y}{4}+\frac{1}{6}$$

Steps for Solving Linear Equation

Multiply 0 and 1 to get 0.

$$12x-33y-2=0$$

Add 33y to both sides. Anything plus zero gives itself.

$$12x-2=33y$$

Add 2 to both sides.

$$12x=33y+2$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{33y+2}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{33y+2}{12}$$

Divide 33y+2 by 12.

$$x=\frac{11y}{4}+\frac{1}{6}$$

Solve for y

$$y=\frac{4x}{11}-\frac{2}{33}$$

Steps for Solving Linear Equation

Multiply 0 and 1 to get 0.

$$12x-33y-2=0$$

Subtract 12x from both sides. Anything subtracted from zero gives its negation.

$$-33y-2=-12x$$

Add 2 to both sides.

$$-33y=-12x+2$$

The equation is in standard form.

$$-33y=2-12x$$

Divide both sides by -33.

$$\frac{-33y}{-33}=\frac{2-12x}{-33}$$

Dividing by -33 undoes the multiplication by -33.

$$y=\frac{2-12x}{-33}$$

Divide -12x+2 by -33.

$$y=\frac{4x}{11}-\frac{2}{33}$$