Solve for x
x=\frac{y}{4}+\frac{4}{3}
Solve for y
y=4x-\frac{16}{3}
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12x-16=3y
Add 3y to both sides. Anything plus zero gives itself.
12x=3y+16
Add 16 to both sides.
\frac{12x}{12}=\frac{3y+16}{12}
Divide both sides by 12.
x=\frac{3y+16}{12}
Dividing by 12 undoes the multiplication by 12.
x=\frac{y}{4}+\frac{4}{3}
Divide 3y+16 by 12.
-3y-16=-12x
Subtract 12x from both sides. Anything subtracted from zero gives its negation.
-3y=-12x+16
Add 16 to both sides.
-3y=16-12x
The equation is in standard form.
\frac{-3y}{-3}=\frac{16-12x}{-3}
Divide both sides by -3.
y=\frac{16-12x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=4x-\frac{16}{3}
Divide -12x+16 by -3.
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