Solve for x
x=\frac{y}{4}+\frac{2}{3}
Solve for y
y=4x-\frac{8}{3}
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12x=8+3y
Add 3y to both sides.
12x=3y+8
The equation is in standard form.
\frac{12x}{12}=\frac{3y+8}{12}
Divide both sides by 12.
x=\frac{3y+8}{12}
Dividing by 12 undoes the multiplication by 12.
x=\frac{y}{4}+\frac{2}{3}
Divide 8+3y by 12.
-3y=8-12x
Subtract 12x from both sides.
\frac{-3y}{-3}=\frac{8-12x}{-3}
Divide both sides by -3.
y=\frac{8-12x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=4x-\frac{8}{3}
Divide 8-12x by -3.
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