Solve for x
x\leq \frac{2}{3}
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12x\leq 5+3
Add 3 to both sides.
12x\leq 8
Add 5 and 3 to get 8.
x\leq \frac{8}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\leq \frac{2}{3}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
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