Solve 12x-6x/9-x/3-5(x/9)=0

$$12 x - \frac { 6 x } { 9 } - \frac { x } { 3 } - 5 ( \frac { x } { 9 } ) = 0$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 9, the least common multiple of 9,3.

$$9\left(12x-\frac{6x}{9}-\frac{x}{3}\right)-5x=0$$

Divide 6x by 9 to get \frac{2}{3}x.

$$9\left(12x-\frac{2}{3}x-\frac{x}{3}\right)-5x=0$$

Combine 12x and -\frac{x}{3} to get \frac{35}{3}x.

$$9\left(\frac{35}{3}x-\frac{2}{3}x\right)-5x=0$$

Use the distributive property to multiply 9 by \frac{35}{3}x-\frac{2}{3}x.

$$9\times \frac{35}{3}x+9\left(-\frac{2}{3}x\right)-5x=0$$

Express 9\times \frac{35}{3} as a single fraction.

$$\frac{9\times 35}{3}x+9\left(-\frac{2}{3}x\right)-5x=0$$

Multiply 9 and 35 to get 315.

$$\frac{315}{3}x+9\left(-\frac{2}{3}x\right)-5x=0$$

Divide 315 by 3 to get 105.

$$105x+9\left(-\frac{2}{3}x\right)-5x=0$$

Combine 105x and -5x to get 100x.

$$100x+9\left(-\frac{2}{3}x\right)=0$$

Multiply 9 and -1 to get -9.

$$100x-9\times \frac{2}{3}x=0$$

Express -9\times \frac{2}{3} as a single fraction.

$$100x+\frac{-9\times 2}{3}x=0$$

Multiply -9 and 2 to get -18.

$$100x+\frac{-18}{3}x=0$$

Divide -18 by 3 to get -6.

$$100x-6x=0$$

Combine 100x and -6x to get 94x.

$$94x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 94 is not equal to 0, x must be equal to 0.

$$x=0$$