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2\left(6x^{4}-5x^{3}+12x^{2}-10x\right)
Factor out 2.
x\left(6x^{3}-5x^{2}+12x-10\right)
Consider 6x^{4}-5x^{3}+12x^{2}-10x. Factor out x.
x^{2}\left(6x-5\right)+2\left(6x-5\right)
Consider 6x^{3}-5x^{2}+12x-10. Do the grouping 6x^{3}-5x^{2}+12x-10=\left(6x^{3}-5x^{2}\right)+\left(12x-10\right), and factor out x^{2} in the first and 2 in the second group.
\left(6x-5\right)\left(x^{2}+2\right)
Factor out common term 6x-5 by using distributive property.
2x\left(6x-5\right)\left(x^{2}+2\right)
Rewrite the complete factored expression. Polynomial x^{2}+2 is not factored since it does not have any rational roots.