Solve for x
x\leq \frac{15}{4}
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12x\leq 110-65
Subtract 65 from both sides.
12x\leq 45
Subtract 65 from 110 to get 45.
x\leq \frac{45}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\leq \frac{15}{4}
Reduce the fraction \frac{45}{12} to lowest terms by extracting and canceling out 3.
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