Solve 12n-3+2n+1-1n-20

$$12 n - 3 + 2 n + 1 - 1 n - 20$$

Evaluate

$$13n-22$$

Solution Steps

Combine 12n and 2n to get 14n.

$$14n-3+1-n-20$$

Add -3 and 1 to get -2.

$$14n-2-n-20$$

Combine 14n and -n to get 13n.

$$13n-2-20$$

Subtract 20 from -2 to get -22.

$$13n-22$$

Differentiate w.r.t. n

$$13$$

Steps Using Derivative Rule for Sum

Combine 12n and 2n to get 14n.

$$\frac{\mathrm{d}}{\mathrm{d}n}(14n-3+1-n-20)$$

Add -3 and 1 to get -2.

$$\frac{\mathrm{d}}{\mathrm{d}n}(14n-2-n-20)$$

Combine 14n and -n to get 13n.

$$\frac{\mathrm{d}}{\mathrm{d}n}(13n-2-20)$$

Subtract 20 from -2 to get -22.

$$\frac{\mathrm{d}}{\mathrm{d}n}(13n-22)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$13n^{1-1}$$

Subtract 1 from 1.

$$13n^{0}$$

For any term t except 0, t^{0}=1.

$$13\times 1$$

For any term t, t\times 1=t and 1t=t.

$$13$$