Solve 12c^{3}d^{4}F^{2}-18c^{2}d^2=^2+30cd^3F^2h

$$12 c ^ { 3 } d ^ { 4 } F ^ { 2 } - 18 c ^ { 2 } d ^ { 2 } = ^ { 2 } + 30 c d ^ { 3 } F ^ { 2 } h$$

Factor

$$6c^{2}d^{2}\left(2cF^{2}d^{2}-3\right)$$

Solution Steps

Factor out 6.

$$6\left(2c^{3}d^{4}F^{2}-3c^{2}d^{2}\right)$$

Consider 2c^{3}d^{4}F^{2}-3c^{2}d^{2}. Factor out c^{2}d^{2}.

$$c^{2}d^{2}\left(2cd^{2}F^{2}-3\right)$$

Rewrite the complete factored expression.

$$6c^{2}d^{2}\left(2cd^{2}F^{2}-3\right)$$

Evaluate

$$6\left(cd\right)^{2}\left(2c\left(Fd\right)^{2}-3\right)$$