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3\left(4ab-6a+2nb-3n\right)
Factor out 3.
2a\left(2b-3\right)+n\left(2b-3\right)
Consider 4ab-6a+2nb-3n. Do the grouping 4ab-6a+2nb-3n=\left(4ab-6a\right)+\left(2nb-3n\right), and factor out 2a in the first and n in the second group.
\left(2b-3\right)\left(2a+n\right)
Factor out common term 2b-3 by using distributive property.
3\left(2b-3\right)\left(n+2a\right)
Rewrite the complete factored expression.