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6ab\left(2ab-c\right)-3ac\left(2ab-c\right)+2ab-c
Do the grouping 12a^{2}b^{2}-6abc+3ac^{2}-6a^{2}bc-c+2ab=\left(12a^{2}b^{2}-6abc\right)+\left(3ac^{2}-6a^{2}bc\right)+\left(-c+2ab\right), and factor out 6ab,-3ac,1 in each of the groups respectively.
\left(2ab-c\right)\left(6ab-3ac+1\right)
Factor out common term 2ab-c by using distributive property.