Solve 12-3^4*(6^4:2^4)+3^8=12

$$12 - 3 ^ { 4 } \cdot ( 6 ^ { 4 } : 2 ^ { 4 } ) + 3 ^ { 8 } = 12$$

Verify

Solution Steps

Calculate 3 to the power of 4 and get 81.

$$12-81\times \frac{6^{4}}{2^{4}}+3^{8}=12$$

Calculate 6 to the power of 4 and get 1296.

$$12-81\times \frac{1296}{2^{4}}+3^{8}=12$$

Calculate 2 to the power of 4 and get 16.

$$12-81\times \frac{1296}{16}+3^{8}=12$$

Divide 1296 by 16 to get 81.

$$12-81\times 81+3^{8}=12$$

Multiply 81 and 81 to get 6561.

$$12-6561+3^{8}=12$$

Subtract 6561 from 12 to get -6549.

$$-6549+3^{8}=12$$

Calculate 3 to the power of 8 and get 6561.

$$-6549+6561=12$$

Add -6549 and 6561 to get 12.

$$12=12$$

Compare 12 and 12.

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