Solve 12-(3+15/8):12/2+3/4:3=

$$12 - ( 3 + \frac { 15 } { 8 } ) : \frac { 12 } { 2 } + \frac { 3 } { 4 } : 3 =$$

Evaluate

$$\frac{183}{16}=11.4375$$

Solution Steps

Convert 3 to fraction \frac{24}{8}.

$$12-\frac{\frac{24}{8}+\frac{15}{8}}{\frac{12}{2}}+\frac{\frac{3}{4}}{3}$$

Since \frac{24}{8} and \frac{15}{8} have the same denominator, add them by adding their numerators.

$$12-\frac{\frac{24+15}{8}}{\frac{12}{2}}+\frac{\frac{3}{4}}{3}$$

Add 24 and 15 to get 39.

$$12-\frac{\frac{39}{8}}{\frac{12}{2}}+\frac{\frac{3}{4}}{3}$$

Divide 12 by 2 to get 6.

$$12-\frac{\frac{39}{8}}{6}+\frac{\frac{3}{4}}{3}$$

Express \frac{\frac{39}{8}}{6} as a single fraction.

$$12-\frac{39}{8\times 6}+\frac{\frac{3}{4}}{3}$$

Multiply 8 and 6 to get 48.

$$12-\frac{39}{48}+\frac{\frac{3}{4}}{3}$$

Reduce the fraction \frac{39}{48} to lowest terms by extracting and canceling out 3.

$$12-\frac{13}{16}+\frac{\frac{3}{4}}{3}$$

Convert 12 to fraction \frac{192}{16}.

$$\frac{192}{16}-\frac{13}{16}+\frac{\frac{3}{4}}{3}$$

Since \frac{192}{16} and \frac{13}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{192-13}{16}+\frac{\frac{3}{4}}{3}$$

Subtract 13 from 192 to get 179.

$$\frac{179}{16}+\frac{\frac{3}{4}}{3}$$

Express \frac{\frac{3}{4}}{3} as a single fraction.

$$\frac{179}{16}+\frac{3}{4\times 3}$$

Cancel out 3 in both numerator and denominator.

$$\frac{179}{16}+\frac{1}{4}$$

Least common multiple of 16 and 4 is 16. Convert \frac{179}{16} and \frac{1}{4} to fractions with denominator 16.

$$\frac{179}{16}+\frac{4}{16}$$

Since \frac{179}{16} and \frac{4}{16} have the same denominator, add them by adding their numerators.

$$\frac{179+4}{16}$$

Add 179 and 4 to get 183.

$$\frac{183}{16}$$

Factor

$$\frac{3 \cdot 61}{2 ^ {4}} = 11\frac{7}{16} = 11.4375$$