Solve 12-sqrt[3]{512}+9*3^4-(6+2-8)div5

$$12 - \sqrt[ 3 ] { 512 } + 9 \times 3 ^ { 4 } - ( 6 + 2 - 8 ) \div 5$$

Evaluate

$$733$$

Solution Steps

Calculate \sqrt[3]{512} and get 8.

$$12-8+9\times 3^{4}-\frac{6+2-8}{5}$$

Subtract 8 from 12 to get 4.

$$4+9\times 3^{4}-\frac{6+2-8}{5}$$

Calculate 3 to the power of 4 and get 81.

$$4+9\times 81-\frac{6+2-8}{5}$$

Multiply 9 and 81 to get 729.

$$4+729-\frac{6+2-8}{5}$$

Add 4 and 729 to get 733.

$$733-\frac{6+2-8}{5}$$

Add 6 and 2 to get 8.

$$733-\frac{8-8}{5}$$

Subtract 8 from 8 to get 0.

$$733-\frac{0}{5}$$

Zero divided by any non-zero number gives zero.

$$733+0$$

Add 733 and 0 to get 733.

$$733$$

Factor

$$733$$