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12x^{2}=16
Add 16 to both sides. Anything plus zero gives itself.
x^{2}=\frac{16}{12}
Divide both sides by 12.
x^{2}=\frac{4}{3}
Reduce the fraction \frac{16}{12} to lowest terms by extracting and canceling out 4.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
Take the square root of both sides of the equation.
12x^{2}-16=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 12\left(-16\right)}}{2\times 12}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 12 for a, 0 for b, and -16 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 12\left(-16\right)}}{2\times 12}
Square 0.
x=\frac{0±\sqrt{-48\left(-16\right)}}{2\times 12}
Multiply -4 times 12.
x=\frac{0±\sqrt{768}}{2\times 12}
Multiply -48 times -16.
x=\frac{0±16\sqrt{3}}{2\times 12}
Take the square root of 768.
x=\frac{0±16\sqrt{3}}{24}
Multiply 2 times 12.
x=\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±16\sqrt{3}}{24} when ± is plus.
x=-\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±16\sqrt{3}}{24} when ± is minus.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
The equation is now solved.