Solve 12m^4-108m^2

$$12 { m }^{ 4 } -108 { m }^{ 2 }$$

Factor

$$12\left(m-3\right)\left(m+3\right)m^{2}$$

Solution Steps

Factor out 12.

$$12\left(m^{4}-9m^{2}\right)$$

Consider m^{4}-9m^{2}. Factor out m^{2}.

$$m^{2}\left(m^{2}-9\right)$$

Consider m^{2}-9. Rewrite m^{2}-9 as m^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(m-3\right)\left(m+3\right)$$

Rewrite the complete factored expression.

$$12m^{2}\left(m-3\right)\left(m+3\right)$$

Evaluate

$$12m^{2}\left(m^{2}-9\right)$$