Solve 12*(2+3x)=42

$$12 \times (2+3x)=42$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Divide both sides by 12.

$$2+3x=\frac{42}{12}$$

Reduce the fraction \frac{42}{12} to lowest terms by extracting and canceling out 6.

$$2+3x=\frac{7}{2}$$

Subtract 2 from both sides.

$$3x=\frac{7}{2}-2$$

Convert 2 to fraction \frac{4}{2}.

$$3x=\frac{7}{2}-\frac{4}{2}$$

Since \frac{7}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{7-4}{2}$$

Subtract 4 from 7 to get 3.

$$3x=\frac{3}{2}$$

Divide both sides by 3.

$$x=\frac{\frac{3}{2}}{3}$$

Express \frac{\frac{3}{2}}{3} as a single fraction.

$$x=\frac{3}{2\times 3}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{1}{2}$$