Solve 12sqrt{2}*4/sqrt{3}=

$$12 \sqrt { 2 } \cdot \frac { 4 } { \sqrt { 3 } } =$$

Evaluate

$$16\sqrt{6}\approx 39.191835885$$

Solution Steps

Rationalize the denominator of \frac{4}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$12\sqrt{2}\times \frac{4\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

The square of \sqrt{3} is 3.

$$12\sqrt{2}\times \frac{4\sqrt{3}}{3}$$

Cancel out 3, the greatest common factor in 12 and 3.

$$4\times 4\sqrt{3}\sqrt{2}$$

Multiply 4 and 4 to get 16.

$$16\sqrt{3}\sqrt{2}$$

To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.

$$16\sqrt{6}$$