Solve for x
x=6\sqrt{6}\approx 14.696938457
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12\sqrt{2}=\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}x
Rationalize the denominator of \frac{2}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
12\sqrt{2}=\frac{2\sqrt{3}}{3}x
The square of \sqrt{3} is 3.
12\sqrt{2}=\frac{2\sqrt{3}x}{3}
Express \frac{2\sqrt{3}}{3}x as a single fraction.
\frac{2\sqrt{3}x}{3}=12\sqrt{2}
Swap sides so that all variable terms are on the left hand side.
2\sqrt{3}x=36\sqrt{2}
Multiply both sides of the equation by 3.
\frac{2\sqrt{3}x}{2\sqrt{3}}=\frac{36\sqrt{2}}{2\sqrt{3}}
Divide both sides by 2\sqrt{3}.
x=\frac{36\sqrt{2}}{2\sqrt{3}}
Dividing by 2\sqrt{3} undoes the multiplication by 2\sqrt{3}.
x=6\sqrt{6}
Divide 36\sqrt{2} by 2\sqrt{3}.
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