Solve 121/9-41/6-32/3

$$12 \frac { 1 } { 9 } - 4 \frac { 1 } { 6 } - 3 \frac { 2 } { 3 }$$

Evaluate

$$\frac{77}{18}\approx 4.277777778$$

Solution Steps

Multiply 12 and 9 to get 108.

$$\frac{108+1}{9}-\frac{4\times 6+1}{6}-\frac{3\times 3+2}{3}$$

Add 108 and 1 to get 109.

$$\frac{109}{9}-\frac{4\times 6+1}{6}-\frac{3\times 3+2}{3}$$

Multiply 4 and 6 to get 24.

$$\frac{109}{9}-\frac{24+1}{6}-\frac{3\times 3+2}{3}$$

Add 24 and 1 to get 25.

$$\frac{109}{9}-\frac{25}{6}-\frac{3\times 3+2}{3}$$

Least common multiple of 9 and 6 is 18. Convert \frac{109}{9} and \frac{25}{6} to fractions with denominator 18.

$$\frac{218}{18}-\frac{75}{18}-\frac{3\times 3+2}{3}$$

Since \frac{218}{18} and \frac{75}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{218-75}{18}-\frac{3\times 3+2}{3}$$

Subtract 75 from 218 to get 143.

$$\frac{143}{18}-\frac{3\times 3+2}{3}$$

Multiply 3 and 3 to get 9.

$$\frac{143}{18}-\frac{9+2}{3}$$

Add 9 and 2 to get 11.

$$\frac{143}{18}-\frac{11}{3}$$

Least common multiple of 18 and 3 is 18. Convert \frac{143}{18} and \frac{11}{3} to fractions with denominator 18.

$$\frac{143}{18}-\frac{66}{18}$$

Since \frac{143}{18} and \frac{66}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{143-66}{18}$$

Subtract 66 from 143 to get 77.

$$\frac{77}{18}$$

Factor

$$\frac{7 \cdot 11}{2 \cdot 3 ^ {2}} = 4\frac{5}{18} = 4.277777777777778$$