Solve 121/4+1/6-17/8

$$12 \frac { 1 } { 4 } + \frac { 1 } { 6 } - 1 \frac { 7 } { 8 }$$

Evaluate

$$\frac{253}{24}\approx 10.541666667$$

Solution Steps

Multiply 12 and 4 to get 48.

$$\frac{48+1}{4}+\frac{1}{6}-\frac{1\times 8+7}{8}$$

Add 48 and 1 to get 49.

$$\frac{49}{4}+\frac{1}{6}-\frac{1\times 8+7}{8}$$

Least common multiple of 4 and 6 is 12. Convert \frac{49}{4} and \frac{1}{6} to fractions with denominator 12.

$$\frac{147}{12}+\frac{2}{12}-\frac{1\times 8+7}{8}$$

Since \frac{147}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\frac{147+2}{12}-\frac{1\times 8+7}{8}$$

Add 147 and 2 to get 149.

$$\frac{149}{12}-\frac{1\times 8+7}{8}$$

Multiply 1 and 8 to get 8.

$$\frac{149}{12}-\frac{8+7}{8}$$

Add 8 and 7 to get 15.

$$\frac{149}{12}-\frac{15}{8}$$

Least common multiple of 12 and 8 is 24. Convert \frac{149}{12} and \frac{15}{8} to fractions with denominator 24.

$$\frac{298}{24}-\frac{45}{24}$$

Since \frac{298}{24} and \frac{45}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{298-45}{24}$$

Subtract 45 from 298 to get 253.

$$\frac{253}{24}$$

Factor

$$\frac{11 \cdot 23}{2 ^ {3} \cdot 3} = 10\frac{13}{24} = 10.541666666666666$$