Solve 121/3+233/4-241/6+76

$$12 \frac { 1 } { 3 } + 23 \frac { 3 } { 4 } - 24 \frac { 1 } { 6 } + 76$$

Evaluate

$$\frac{1055}{12}\approx 87.916666667$$

Solution Steps

Multiply 12 and 3 to get 36.

$$\frac{36+1}{3}+\frac{23\times 4+3}{4}-\frac{24\times 6+1}{6}+76$$

Add 36 and 1 to get 37.

$$\frac{37}{3}+\frac{23\times 4+3}{4}-\frac{24\times 6+1}{6}+76$$

Multiply 23 and 4 to get 92.

$$\frac{37}{3}+\frac{92+3}{4}-\frac{24\times 6+1}{6}+76$$

Add 92 and 3 to get 95.

$$\frac{37}{3}+\frac{95}{4}-\frac{24\times 6+1}{6}+76$$

Least common multiple of 3 and 4 is 12. Convert \frac{37}{3} and \frac{95}{4} to fractions with denominator 12.

$$\frac{148}{12}+\frac{285}{12}-\frac{24\times 6+1}{6}+76$$

Since \frac{148}{12} and \frac{285}{12} have the same denominator, add them by adding their numerators.

$$\frac{148+285}{12}-\frac{24\times 6+1}{6}+76$$

Add 148 and 285 to get 433.

$$\frac{433}{12}-\frac{24\times 6+1}{6}+76$$

Multiply 24 and 6 to get 144.

$$\frac{433}{12}-\frac{144+1}{6}+76$$

Add 144 and 1 to get 145.

$$\frac{433}{12}-\frac{145}{6}+76$$

Least common multiple of 12 and 6 is 12. Convert \frac{433}{12} and \frac{145}{6} to fractions with denominator 12.

$$\frac{433}{12}-\frac{290}{12}+76$$

Since \frac{433}{12} and \frac{290}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{433-290}{12}+76$$

Subtract 290 from 433 to get 143.

$$\frac{143}{12}+76$$

Convert 76 to fraction \frac{912}{12}.

$$\frac{143}{12}+\frac{912}{12}$$

Since \frac{143}{12} and \frac{912}{12} have the same denominator, add them by adding their numerators.

$$\frac{143+912}{12}$$

Add 143 and 912 to get 1055.

$$\frac{1055}{12}$$

Factor

$$\frac{5 \cdot 211}{2 ^ {2} \cdot 3} = 87\frac{11}{12} = 87.91666666666667$$