Solve 12*(-2/3)*(-3/4)^2

$$12 \cdot ( - \frac { 2 } { 3 } ) \cdot ( - \frac { 3 } { 4 } ) ^ { 2 }$$

Evaluate

$$-\frac{9}{2}=-4.5$$

Solution Steps

Express 12\left(-\frac{2}{3}\right) as a single fraction.

$$\frac{12\left(-2\right)}{3}\left(-\frac{3}{4}\right)^{2}$$

Multiply 12 and -2 to get -24.

$$\frac{-24}{3}\left(-\frac{3}{4}\right)^{2}$$

Divide -24 by 3 to get -8.

$$-8\left(-\frac{3}{4}\right)^{2}$$

Calculate -\frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$-8\times \frac{9}{16}$$

Express -8\times \frac{9}{16} as a single fraction.

$$\frac{-8\times 9}{16}$$

Multiply -8 and 9 to get -72.

$$\frac{-72}{16}$$

Reduce the fraction \frac{-72}{16} to lowest terms by extracting and canceling out 8.

$$-\frac{9}{2}$$

Factor

$$-\frac{9}{2} = -4\frac{1}{2} = -4.5$$