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12^{y-6}=3
Use the rules of exponents and logarithms to solve the equation.
\log(12^{y-6})=\log(3)
Take the logarithm of both sides of the equation.
\left(y-6\right)\log(12)=\log(3)
The logarithm of a number raised to a power is the power times the logarithm of the number.
y-6=\frac{\log(3)}{\log(12)}
Divide both sides by \log(12).
y-6=\log_{12}\left(3\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
y=\log_{12}\left(3\right)-\left(-6\right)
Add 6 to both sides of the equation.