Solve 12=a*7^2+(-2)*7+19

$$12 = a \cdot 7 ^ { 2 } + ( - 2 ) \cdot 7 + 19$$

Solve for a

$$a=\frac{1}{7}\approx 0.142857143$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$12=a\times 49-2\times 7+19$$

Multiply -2 and 7 to get -14.

$$12=a\times 49-14+19$$

Add -14 and 19 to get 5.

$$12=a\times 49+5$$

Swap sides so that all variable terms are on the left hand side.

$$a\times 49+5=12$$

Subtract 5 from both sides.

$$a\times 49=12-5$$

Subtract 5 from 12 to get 7.

$$a\times 49=7$$

Divide both sides by 49.

$$a=\frac{7}{49}$$

Reduce the fraction \frac{7}{49} to lowest terms by extracting and canceling out 7.

$$a=\frac{1}{7}$$