Solve for z
z=1
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\frac{12}{15}=z-\frac{1}{5}
Divide both sides by 15.
\frac{4}{5}=z-\frac{1}{5}
Reduce the fraction \frac{12}{15} to lowest terms by extracting and canceling out 3.
z-\frac{1}{5}=\frac{4}{5}
Swap sides so that all variable terms are on the left hand side.
z=\frac{4}{5}+\frac{1}{5}
Add \frac{1}{5} to both sides.
z=\frac{4+1}{5}
Since \frac{4}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.
z=\frac{5}{5}
Add 4 and 1 to get 5.
z=1
Divide 5 by 5 to get 1.
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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