Solve for a
a = \frac{40}{3} = 13\frac{1}{3} \approx 13.333333333
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\frac{12}{0.9}=a
Divide both sides by 0.9.
\frac{120}{9}=a
Expand \frac{12}{0.9} by multiplying both numerator and the denominator by 10.
\frac{40}{3}=a
Reduce the fraction \frac{120}{9} to lowest terms by extracting and canceling out 3.
a=\frac{40}{3}
Swap sides so that all variable terms are on the left hand side.
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Limits
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