Solve 12+30:[(6+42-8*(-2))-24]

$$12 + 30 : [ ( 6 + 42 - 8 \cdot ( - 2 ) ) - 24 ]$$

Evaluate

$$\frac{51}{4}=12.75$$

Solution Steps

Add 6 and 42 to get 48.

$$12+\frac{30}{48-8\left(-2\right)-24}$$

Multiply 8 and -2 to get -16.

$$12+\frac{30}{48-\left(-16\right)-24}$$

The opposite of -16 is 16.

$$12+\frac{30}{48+16-24}$$

Add 48 and 16 to get 64.

$$12+\frac{30}{64-24}$$

Subtract 24 from 64 to get 40.

$$12+\frac{30}{40}$$

Reduce the fraction \frac{30}{40} to lowest terms by extracting and canceling out 10.

$$12+\frac{3}{4}$$

Convert 12 to fraction \frac{48}{4}.

$$\frac{48}{4}+\frac{3}{4}$$

Since \frac{48}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{48+3}{4}$$

Add 48 and 3 to get 51.

$$\frac{51}{4}$$

Factor

$$\frac{3 \cdot 17}{2 ^ {2}} = 12\frac{3}{4} = 12.75$$