Solve 12+2y-3z=11+4y-2z

$$12 + 2 y - 3 z = 11 + 4 y - 2 z$$

Solve for y

$$y=\frac{1-z}{2}$$

Steps for Solving Linear Equation

Subtract 4y from both sides.

$$12+2y-3z-4y=11-2z$$

Combine 2y and -4y to get -2y.

$$12-2y-3z=11-2z$$

Subtract 12 from both sides.

$$-2y-3z=11-2z-12$$

Subtract 12 from 11 to get -1.

$$-2y-3z=-1-2z$$

Add 3z to both sides.

$$-2y=-1-2z+3z$$

Combine -2z and 3z to get z.

$$-2y=-1+z$$

The equation is in standard form.

$$-2y=z-1$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{z-1}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{z-1}{-2}$$

Divide -1+z by -2.

$$y=\frac{1-z}{2}$$

Solve for z

$$z=1-2y$$

Steps for Solving Linear Equation

Add 2z to both sides.

$$12+2y-3z+2z=11+4y$$

Combine -3z and 2z to get -z.

$$12+2y-z=11+4y$$

Subtract 12 from both sides.

$$2y-z=11+4y-12$$

Subtract 12 from 11 to get -1.

$$2y-z=-1+4y$$

Subtract 2y from both sides.

$$-z=-1+4y-2y$$

Combine 4y and -2y to get 2y.

$$-z=-1+2y$$

The equation is in standard form.

$$-z=2y-1$$

Divide both sides by -1.

$$\frac{-z}{-1}=\frac{2y-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$z=\frac{2y-1}{-1}$$

Divide -1+2y by -1.

$$z=1-2y$$