Solve 12+(3+(-4+5-7+3(4-2(2))+8-12)+2-7)=

$$12 + ( 3 + ( - 4 + 5 - 7 + 3 ( 4 - 2 ( 2 ) ) + 8 - 12 ) + 2 - 7 ) =$$

Evaluate

$$0$$

Solution Steps

Add 12 and 3 to get 15.

$$15-4+5-7+3\left(4-2\times 2\right)+8-12+2-7$$

Subtract 4 from 15 to get 11.

$$11+5-7+3\left(4-2\times 2\right)+8-12+2-7$$

Add 11 and 5 to get 16.

$$16-7+3\left(4-2\times 2\right)+8-12+2-7$$

Subtract 7 from 16 to get 9.

$$9+3\left(4-2\times 2\right)+8-12+2-7$$

Multiply 2 and 2 to get 4.

$$9+3\left(4-4\right)+8-12+2-7$$

Subtract 4 from 4 to get 0.

$$9+3\times 0+8-12+2-7$$

Multiply 3 and 0 to get 0.

$$9+0+8-12+2-7$$

Add 9 and 0 to get 9.

$$9+8-12+2-7$$

Add 9 and 8 to get 17.

$$17-12+2-7$$

Subtract 12 from 17 to get 5.

$$5+2-7$$

Add 5 and 2 to get 7.

$$7-7$$

Subtract 7 from 7 to get 0.

$$0$$

Factor

$$0$$