Solve 1125+12/3-25/6*-8/27

$$1125+ 1 \frac { 2 } { 3 } - 2 \frac { 5 } { 6 } \times - \frac{ 8 }{ 27 }$$

Evaluate

$$\frac{91328}{81}\approx 1127.50617284$$

Solution Steps

Multiply 1 and 3 to get 3.

$$1125+\frac{3+2}{3}-\frac{2\times 6+5}{6}\left(-\frac{8}{27}\right)$$

Add 3 and 2 to get 5.

$$1125+\frac{5}{3}-\frac{2\times 6+5}{6}\left(-\frac{8}{27}\right)$$

Convert 1125 to fraction \frac{3375}{3}.

$$\frac{3375}{3}+\frac{5}{3}-\frac{2\times 6+5}{6}\left(-\frac{8}{27}\right)$$

Since \frac{3375}{3} and \frac{5}{3} have the same denominator, add them by adding their numerators.

$$\frac{3375+5}{3}-\frac{2\times 6+5}{6}\left(-\frac{8}{27}\right)$$

Add 3375 and 5 to get 3380.

$$\frac{3380}{3}-\frac{2\times 6+5}{6}\left(-\frac{8}{27}\right)$$

Multiply 2 and 6 to get 12.

$$\frac{3380}{3}-\frac{12+5}{6}\left(-\frac{8}{27}\right)$$

Add 12 and 5 to get 17.

$$\frac{3380}{3}-\frac{17}{6}\left(-\frac{8}{27}\right)$$

Multiply \frac{17}{6} times -\frac{8}{27} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3380}{3}-\frac{17\left(-8\right)}{6\times 27}$$

Do the multiplications in the fraction \frac{17\left(-8\right)}{6\times 27}.

$$\frac{3380}{3}-\frac{-136}{162}$$

Reduce the fraction \frac{-136}{162} to lowest terms by extracting and canceling out 2.

$$\frac{3380}{3}-\left(-\frac{68}{81}\right)$$

The opposite of -\frac{68}{81} is \frac{68}{81}.

$$\frac{3380}{3}+\frac{68}{81}$$

Least common multiple of 3 and 81 is 81. Convert \frac{3380}{3} and \frac{68}{81} to fractions with denominator 81.

$$\frac{91260}{81}+\frac{68}{81}$$

Since \frac{91260}{81} and \frac{68}{81} have the same denominator, add them by adding their numerators.

$$\frac{91260+68}{81}$$

Add 91260 and 68 to get 91328.

$$\frac{91328}{81}$$

Factor

$$\frac{2 ^ {6} \cdot 1427}{3 ^ {4}} = 1127\frac{41}{81} = 1127.5061728395062$$