Solve 1100=48400/frac{484R{484+R}}

$$1100 = \frac{ 48400 }{ \frac{ 484R }{ 484+R } }$$

Solve for R

$$R = \frac{242}{5} = 48\frac{2}{5} = 48.4$$

Steps for Solving Linear Equation

Variable R cannot be equal to -484 since division by zero is not defined. Divide 48400 by \frac{484R}{484+R} by multiplying 48400 by the reciprocal of \frac{484R}{484+R}.

$$1100=\frac{48400\left(484+R\right)}{484R}$$

Cancel out 484 in both numerator and denominator.

$$1100=\frac{100\left(R+484\right)}{R}$$

Use the distributive property to multiply 100 by R+484.

$$1100=\frac{100R+48400}{R}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{100R+48400}{R}=1100$$

Variable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by R.

$$100R+48400=1100R$$

Subtract 1100R from both sides.

$$100R+48400-1100R=0$$

Combine 100R and -1100R to get -1000R.

$$-1000R+48400=0$$

Subtract 48400 from both sides. Anything subtracted from zero gives its negation.

$$-1000R=-48400$$

Divide both sides by -1000.

$$R=\frac{-48400}{-1000}$$

Reduce the fraction \frac{-48400}{-1000} to lowest terms by extracting and canceling out -200.

$$R=\frac{242}{5}$$