Solve 11.3*3/10-12.6*3/20+12.5*(-3/5)=

$$11.3 \times \frac { 3 } { 10 } - 12.6 \times \frac { 3 } { 20 } + 12.5 \times ( - \frac { 3 } { 5 } ) =$$

Evaluate

$$-6$$

Solution Steps

Convert decimal number 11.3 to fraction \frac{113}{10}.

$$\frac{113}{10}\times \frac{3}{10}-12.6\times \frac{3}{20}+12.5\left(-\frac{3}{5}\right)$$

Multiply \frac{113}{10} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{113\times 3}{10\times 10}-12.6\times \frac{3}{20}+12.5\left(-\frac{3}{5}\right)$$

Do the multiplications in the fraction \frac{113\times 3}{10\times 10}.

$$\frac{339}{100}-12.6\times \frac{3}{20}+12.5\left(-\frac{3}{5}\right)$$

Convert decimal number 12.6 to fraction \frac{126}{10}. Reduce the fraction \frac{126}{10} to lowest terms by extracting and canceling out 2.

$$\frac{339}{100}-\frac{63}{5}\times \frac{3}{20}+12.5\left(-\frac{3}{5}\right)$$

Multiply \frac{63}{5} times \frac{3}{20} by multiplying numerator times numerator and denominator times denominator.

$$\frac{339}{100}-\frac{63\times 3}{5\times 20}+12.5\left(-\frac{3}{5}\right)$$

Do the multiplications in the fraction \frac{63\times 3}{5\times 20}.

$$\frac{339}{100}-\frac{189}{100}+12.5\left(-\frac{3}{5}\right)$$

Since \frac{339}{100} and \frac{189}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{339-189}{100}+12.5\left(-\frac{3}{5}\right)$$

Subtract 189 from 339 to get 150.

$$\frac{150}{100}+12.5\left(-\frac{3}{5}\right)$$

Reduce the fraction \frac{150}{100} to lowest terms by extracting and canceling out 50.

$$\frac{3}{2}+12.5\left(-\frac{3}{5}\right)$$

Convert decimal number 12.5 to fraction \frac{125}{10}. Reduce the fraction \frac{125}{10} to lowest terms by extracting and canceling out 5.

$$\frac{3}{2}+\frac{25}{2}\left(-\frac{3}{5}\right)$$

Multiply \frac{25}{2} times -\frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{2}+\frac{25\left(-3\right)}{2\times 5}$$

Do the multiplications in the fraction \frac{25\left(-3\right)}{2\times 5}.

$$\frac{3}{2}+\frac{-75}{10}$$

Reduce the fraction \frac{-75}{10} to lowest terms by extracting and canceling out 5.

$$\frac{3}{2}-\frac{15}{2}$$

Since \frac{3}{2} and \frac{15}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-15}{2}$$

Subtract 15 from 3 to get -12.

$$\frac{-12}{2}$$

Divide -12 by 2 to get -6.

$$-6$$

Factor

$$-6$$