Solve 11x-(x-20)=2x-(1quad+x)

$$11 x - ( x - 20 ) = 2 x - ( 1 \quad + x )$$

Solve for x

$$x = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

Steps for Solving Linear Equation

To find the opposite of x-20, find the opposite of each term.

$$11x-x-\left(-20\right)=2x-\left(1+x\right)$$

The opposite of -20 is 20.

$$11x-x+20=2x-\left(1+x\right)$$

Combine 11x and -x to get 10x.

$$10x+20=2x-\left(1+x\right)$$

To find the opposite of 1+x, find the opposite of each term.

$$10x+20=2x-1-x$$

Combine 2x and -x to get x.

$$10x+20=x-1$$

Subtract x from both sides.

$$10x+20-x=-1$$

Combine 10x and -x to get 9x.

$$9x+20=-1$$

Subtract 20 from both sides.

$$9x=-1-20$$

Subtract 20 from -1 to get -21.

$$9x=-21$$

Divide both sides by 9.

$$x=\frac{-21}{9}$$

Reduce the fraction \frac{-21}{9} to lowest terms by extracting and canceling out 3.

$$x=-\frac{7}{3}$$