Factor
\left(11b-6\right)\left(b^{2}+1\right)
Evaluate
\left(11b-6\right)\left(b^{2}+1\right)
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b^{2}\left(11b-6\right)+11b-6
Do the grouping 11b^{3}-6b^{2}+11b-6=\left(11b^{3}-6b^{2}\right)+\left(11b-6\right), and factor out b^{2} in 11b^{3}-6b^{2}.
\left(11b-6\right)\left(b^{2}+1\right)
Factor out common term 11b-6 by using distributive property. Polynomial b^{2}+1 is not factored since it does not have any rational roots.
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