Solve 11ab-5ab=(11-5)ab=6ab

$$11 a b - 5 a b = ( 11 - 5 ) a b = 6 a b$$

Evaluate (complex solution)

Solution Steps

Combine 11ab and -5ab to get 6ab.

$$6ab=\left(11-5\right)ab\text{ and }\left(11-5\right)ab=6ab$$

Subtract 5 from 11 to get 6.

$$6ab=6ab\text{ and }\left(11-5\right)ab=6ab$$

Subtract 5 from 11 to get 6.

$$6ab=6ab\text{ and }6ab=6ab$$

Subtract 6ab from both sides.

$$6ab-6ab=0\text{ and }6ab=6ab$$

Combine 6ab and -6ab to get 0.

$$0=0\text{ and }6ab=6ab$$

Compare 0 and 0.

$$\text{true}\text{ and }6ab=6ab$$

Subtract 6ab from both sides.

$$\text{true}\text{ and }6ab-6ab=0$$

Combine 6ab and -6ab to get 0.

$$\text{true}\text{ and }0=0$$

Compare 0 and 0.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$

Solve for b

$$b\in \mathrm{R}$$

Solve for a

$$a\in \mathrm{R}$$