Solve 11-(5-1)+1/2%6-10div5-11

$$11 - ( 5 - 1 ) + \frac { 1 } { 2 } \% 6 - 10 \div 5 - 11$$

Evaluate

$$-\frac{597}{100}=-5.97$$

Solution Steps

Subtract 1 from 5 to get 4.

$$11-4+\frac{\frac{1}{2}}{100}\times 6-\frac{10}{5}-11$$

Subtract 4 from 11 to get 7.

$$7+\frac{\frac{1}{2}}{100}\times 6-\frac{10}{5}-11$$

Express \frac{\frac{1}{2}}{100} as a single fraction.

$$7+\frac{1}{2\times 100}\times 6-\frac{10}{5}-11$$

Multiply 2 and 100 to get 200.

$$7+\frac{1}{200}\times 6-\frac{10}{5}-11$$

Multiply \frac{1}{200} and 6 to get \frac{6}{200}.

$$7+\frac{6}{200}-\frac{10}{5}-11$$

Reduce the fraction \frac{6}{200} to lowest terms by extracting and canceling out 2.

$$7+\frac{3}{100}-\frac{10}{5}-11$$

Convert 7 to fraction \frac{700}{100}.

$$\frac{700}{100}+\frac{3}{100}-\frac{10}{5}-11$$

Since \frac{700}{100} and \frac{3}{100} have the same denominator, add them by adding their numerators.

$$\frac{700+3}{100}-\frac{10}{5}-11$$

Add 700 and 3 to get 703.

$$\frac{703}{100}-\frac{10}{5}-11$$

Divide 10 by 5 to get 2.

$$\frac{703}{100}-2-11$$

Convert 2 to fraction \frac{200}{100}.

$$\frac{703}{100}-\frac{200}{100}-11$$

Since \frac{703}{100} and \frac{200}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{703-200}{100}-11$$

Subtract 200 from 703 to get 503.

$$\frac{503}{100}-11$$

Convert 11 to fraction \frac{1100}{100}.

$$\frac{503}{100}-\frac{1100}{100}$$

Since \frac{503}{100} and \frac{1100}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{503-1100}{100}$$

Subtract 1100 from 503 to get -597.

$$-\frac{597}{100}$$

Factor

$$-\frac{597}{100} = -5\frac{97}{100} = -5.97$$